together_ai/deepseek-ai/DeepSeek-R1

Steps:

1. Extract the number of hours and minutes from the string.
2. Convert the hours to minutes (1 hour = 60 minutes) and add the minutes.

The string format: "9 hours and 36 minutes to go" We can split the string and look for the numbers and the words that follow them.

Approach:

• Split the string by spaces.
• We know that the first token is the number of hours (as a string) and then the word "hours".
• Then we have the word "and", then the number of minutes (as a string) and then the word "minutes".

However, note that the string might vary. Let's break it down:

Example: "9 hours and 36 minutes to go"

Tokens: ['9', 'hours', 'and', '36', 'minutes', 'to', 'go']

We can look for the index of "hours" and the index of "minutes".

Steps in code:

1. Split the string: tokens = s.split()
2. Find the index of "hours": it will be at index 1 in this example, then the hour value is at index 0.
3. Similarly, "minutes" is at index 4, then the minute value is at index 3.

But what if the string is different? For example: "1 hour and 1 minute to go" (singular) or without "and"?

Since the problem says "9 hours and 36 minutes", we assume the format is fixed? But let's consider the problem says exactly that.

However, to be safe, we can:

• Look for the token that has a numeric string? But note: the string might have other numbers? Probably not.

Alternatively, we can use:

hours_index = tokens.index('hours') # but what if singular? then we have 'hour' minutes_index = tokens.index('minutes') # similarly, might be 'minute'

But the problem says "hours" and "minutes", so we assume plural.

However, the problem says: "9 hours and 36 minutes", so we have plurals.

But to be safe, we can also check for singular? The problem doesn't specify.

Since the problem is fixed to one string, we can do:

tokens = s.split() hours = 0 minutes = 0

If we find a token that is a number and the next token is either 'hours' or 'hour', then we take that number as hours. Similarly, if we find a token that is a number and the next token is either 'minutes' or 'minute', then we take that number as minutes.

Steps:

tokens = s.split() i = 0 while i < len(tokens): if tokens[i].isdigit(): num = int(tokens[i]) if i+1 < len(tokens): next_word = tokens[i+1] if next_word in ['hours', 'hour']: hours = num i += 1 # skip next token elif next_word in ['minutes', 'minute']: minutes = num i += 1 # skip next token i += 1 else: i += 1

Then total_minutes = hours * 60 + minutes

However, note the example: "9 hours and 36 minutes"

But what if the string is: "36 minutes and 9 hours"? Then we would still get the same.

But the problem says the string is "9 hours and 36 minutes", so order might be fixed? But the above code works regardless of order.

But note: the string might have the word "and" in between? We don't care about non-digit and non-time unit words.

Let's test with the example:

tokens: ['9', 'hours', 'and', '36', 'minutes', 'to', 'go']

i=0: token '9' is digit -> num=9, next token='hours' -> hours=9, then we set i += 2? Actually, we do: we set hours=9, then we skip the next token by doing i += 1 inside the if (so i becomes 1) and then the outer i +=1 makes i=2. Then i=2: token 'and' -> skip, i becomes 3. i=3: token '36' -> digit, next token='minutes' -> minutes=36, then skip next token (so i becomes 4) and then outer i becomes 5. Then i=5: 'to' -> skip, i=6: 'go' -> skip.

So we get hours=9, minutes=36.

total_minutes = 9*60 + 36 = 540 + 36 = 576.

But what if the string is: "There are 9 hours and 36 minutes to go"? Then tokens: ['There', 'are', '9', 'hours', ...]

We need to capture the 9 and 36.

With the above algorithm:

  i=0: 'There' -> skip -> i=1
  i=1: 'are' -> skip -> i=2
  i=2: '9' -> digit -> next token is 'hours' -> set hours=9, then we skip the next token (so we skip 'hours') and then we do i+=1 -> i=3, then the outer i+=1 makes i=4? Actually:

    Inside the if block for digit:
      we set hours=9, then we do i += 1 (so i becomes 3) and then we break out of the if and then the outer i +=1 makes i=4.

    Then i=4: token 'and' -> skip -> i=5
    i=5: token '36' -> digit -> next token is 'minutes' -> set minutes=36, then we do i +=1 (so i becomes 6) and then outer i +=1 makes i=7.

    Then we are done.

So it works.

However, what if we have: "1 hour 30 minutes" (without and)? Then:

  tokens: ['1','hour','30','minutes']

  i=0: 1 -> digit, next token='hour' -> set hours=1, then i becomes 1 (inside) and then outer makes i=2.
  i=2: 30 -> digit, next token='minutes' -> set minutes=30, then i becomes 3 (inside) and then outer makes i=4 -> done.

So it works.

But what if we have: "30 minutes 1 hour"? Then:

  i=0: 30 -> digit, next token='minutes' -> set minutes=30, then i becomes 1 (inside) and then outer makes i=2.
  i=2: 1 -> digit, next token='hour' -> set hours=1, then i becomes 3 (inside) and then outer makes i=4 -> done.

So it works.

Therefore, we can write a function that parses the string and returns total minutes.

However, note: the problem says "9 hours and 36 minutes to go", so we can also use:

  total_minutes = 9*60 + 36 = 576

But we are to write code that can handle such a string.

Let's code accordingly.

Edge: if the string doesn't have hours or minutes, then we set that part to 0.

Example: "36 minutes to go" -> then hours=0, minutes=36.

Similarly, "2 hours to go" -> minutes=0.

We'll do:

  hours = 0
  minutes = 0

Then traverse.

Code:

  def convert_to_minutes(s):
      tokens = s.split()
      i = 0
      hours = 0
      minutes = 0
      while i < len(tokens):
          if tokens[i].isdigit():
              num = int(tokens[i])
              if i+1 < len(tokens):
                  next_token = tokens[i+1].lower()   # to handle case if it's 'Hour' or 'HOUR'? but problem is lowercase? but let's make it case-insensitive for unit
                  if next_token in ['hours', 'hour']:
                      hours = num
                      i += 1   # skip the next token
                  elif next_token in ['minutes', 'minute']:
                      minutes = num
                      i += 1   # skip the next token
              # else: if there is no next token, then we just take the number? but then it's not followed by unit -> ignore?
              # So we do nothing and just move on.
          i += 1

      return hours * 60 + minutes

Let's test with the example: "9 hours and 36 minutes to go"

  tokens: ['9','hours','and','36','minutes','to','go']

  i=0: token '9' -> digit -> num=9, next_token='hours' -> which is in the list -> set hours=9, then we set i +=1 (so i becomes 1) and then the outer i+=1 makes i=2.
  i=2: token 'and' -> not digit -> i becomes 3.
  i=3: token '36' -> digit -> num=36, next_token='minutes' -> in the list -> set

Steps:

1. Extract the number of hours and the number of minutes.
2. There are two numbers: one for hours and one for minutes.
3. We note that 1 hour = 60 minutes.
4. So total minutes = (hours * 60) + minutes.

How to parse? The string has: "4 hours and 7 minutes to go"

We can split the string and look for the numbers and the words that follow.

Approach:

• Split the string by spaces: ['4', 'hours', 'and', '7', 'minutes', 'to', 'go']
• We can look for the word "hours" and take the token before it? But note: the token before "hours" is '4'. Similarly, the token before "minutes" is '7'.

However, note the structure: [number] hours and [number] minutes

Steps for parsing:

1. Split the string.
2. Traverse the tokens. When we find a token that is a number (like '4', '7'), then check the next token to see if it is "hours", "minutes", etc.

But note: the string might be in different orders? However, the problem states the exact string.

Alternatively, we can use:

• Find the index of "hours", then the token at index-1 is the hour string.
• Find the index of "minutes", then the token at index-1 is the minute string.

However, note: what if the string is "1 hour" (singular) or "10 minutes"? But the example uses plural.

But the problem says: "4 hours and 7 minutes to go", so we can rely on the words.

Steps: tokens = s.split() Find the index of "hours": if "hours" in tokens: then index_h = tokens.index("hours") then hour_str = tokens[index_h - 1]

Similarly, for minutes: if "minutes" in tokens: index_m = tokens.index("minutes") then minute_str = tokens[index_m - 1]

But note: what if the string is "4 hours 7 minutes" without "and"? The example has "and".

We can also use regular expressions.

Alternatively, we can do:

import re pattern = r'(\d+)\shours?\sand?\s*(\d+)\s*minutes?'

However, let's design a regex:

pattern = r'(\d+)\shours?\s(?:and\s*)?(\d+)\s*minutes?'

But note: the example has "and", but what if it doesn't? The problem says the exact string, so we can rely on the given format.

Actually, the problem says: "4 hours and 7 minutes to go"

So we can do:

match = re.search(r'(\d+) hours and (\d+) minutes', s)

if match: hours = int(match.group(1)) minutes = int(match.group(2))

Then total_minutes = hours * 60 + minutes

Let's code accordingly.

Example: s = "4 hours and 7 minutes to go"

We want to extract 4 and 7.

Implementation:

import re

pattern = r'(\d+) hours and (\d+) minutes'

But note: what if the numbers are not single digits? The regex \d+ will handle any integer.

Also, the string has "to go" at the end, but the pattern we are matching is in the beginning.

We can use:

    match = re.search(r'(\d+)\s*hours?\s*and\s*(\d+)\s*minutes?', s, re.IGNORECASE)

But note: the example has "hours" and "minutes" (plural). The pattern uses 's?' to allow optional 's'? But the example has 's'. However, the problem says exactly that string.

Since the problem is fixed, we can do without regex too, but regex is straightforward.

However, if we don't want to use regex:

    tokens = s.split()
    # We know the structure: [number] [word for hour] and [number] [word for minute] ... 
    # We can traverse and pick numbers that are followed by time unit words.

    hours = None
    minutes = None

    for i, token in enumerate(tokens):
        if token == 'hours' and i>0:
            try:
                hours = int(tokens[i-1])
            except:
                pass
        elif token == 'minutes' and i>0:
            try:
                minutes = int(tokens[i-1])
            except:
                pass

    But note: the word "and" is in between. It doesn't affect because we are only looking for the words "hours" and "minutes".

    However, what if the string is "I have 4 hours and 7 minutes to go"? Then the token before "hours" is still the hour number.

    But the example: 
        tokens = ['4', 'hours', 'and', '7', 'minutes', 'to', 'go']

    For "hours": i=1, tokens[0] = '4' -> hours=4
    For "minutes": i=4, tokens[3] = '7' -> minutes=7

    But wait: at i=4, the token is "minutes", then the previous token is at index 3 which is '7'. However, note that the token at index 3 is actually the number for minutes.

    This method would work.

    However, what if there are multiple numbers? For example: "I have 3 hours and 30 minutes to go, and then 2 hours more". But the problem says the exact string: "4 hours and 7 minutes to go". So we can assume only two numbers.

    But to be safe, we break after we found both? Or we take the last occurrence? Actually, the example has only two.

    Alternatively, we can use:

        hour_index = tokens.index('hours')   # This returns the first occurrence of 'hours'
        minute_index = tokens.index('minutes') # first occurrence of 'minutes'

        hours = int(tokens[hour_index-1])
        minutes = int(tokens[minute_index-1])

    This is simpler.

    However, what if the string does not contain "hours" or "minutes"? Then we get an exception.

    Since the problem states the exact string, we can assume they are present.

    Let's code accordingly.

    Steps without regex:

        tokens = s.split()
        if 'hours' in tokens and 'minutes' in tokens:
            hour_index = tokens.index('hours')
            minute_index = tokens.index('minutes')
            try:
                hours = int(tokens[hour_index-1])
                minutes = int(tokens[minute_index-1])
            except:
                # If conversion fails, then we return 0? or raise error?
                # According to the problem, we expect numbers, so we can assume they are integers.
                hours = 0
                minutes = 0
        else:
            # If one of them is missing, then we try to get only one?
            # But the problem says both are present.
            hours = 0
            minutes = 0

        total_minutes = hours * 60 + minutes

    But note: what if the string is "1 hour and 1 minute" (singular)? Then we would be looking for "hours" and "minutes", which are not found.

    The problem says: "4 hours and 7 minutes", so plural. But what if we get singular? The problem does not specify.

    Since the problem says the exact string, we can assume plural.

    However, to be safe, we can also check for singular forms? But the problem says the exact string.

    Let's stick to the exact string: "4 hours and 7 minutes to go"

    But the problem says: "4 hours and 7 minutes to go", so we can rely on that.

    Alternatively, we can use a more robust method: using a list of possible hour words and minute words.

    But for simplicity, and since the input is fixed, we can do:

        if "hours" in tokens:
            # ... as above
        elif "hour" in tokens:
            # then use that

    But the problem says "hours", so we don't need.

    We'll code without regex for now.

    However, the problem says: "4 hours and 7 minutes to go", so we can also do:

        # We know the string format: [number] hours and [number] minutes ...
        # We can split by spaces and then the first token is the hour, the fourth token is the minute? 
        # tokens[0] = '4', tokens[1]='hours', tokens[2]='and', tokens[3]='7', tokens[4]='minutes'

        So: 
            hours = int(tokens[0])
            minutes = int(tokens[3])

    This is even simpler and more efficient.

    But what if the string is: "There are 4 hours and 7 minutes to go"?
    Then tokens[0] = 'There', which is not the hour.

    So we cannot rely on fixed positions.

    Therefore, we go back to the index method.

    Code:

        tokens = s.split()
        if 'hours' in

However, note that the string might have variations. In this case, it's fixed: "1 hours and 11 minutes to go"

We can split the string and look for the numbers and the words that come after them.

Approach:

• Split the string by spaces.
• We know that the first token is the hour number (if present) and then the word "hours" (or "hour") might follow.
• Similarly, we look for the token that is the minute number and then the word "minutes" (or "minute").

But note: the string might not always have hours? or might have only minutes? However, the problem states: "1 hours and 11 minutes"

Let's break down the string: tokens = ["1", "hours", "and", "11", "minutes", "to", "go"]

We can traverse the tokens and when we find a token that is a number, then check the next token to see if it's "hours", "hour", "minutes", or "minute".

Steps for extraction: total_minutes = 0 tokens = input_string.split() for i in range(len(tokens)): if tokens[i].isdigit(): num = int(tokens[i]) if i+1 < len(tokens): next_word = tokens[i+1].lower() if next_word in ['hour', 'hours']: total_minutes += num * 60 elif next_word in ['minute', 'minutes']: total_minutes += num

However, note: what if the number is not a single token? For example, "one hour" -> but in our case, it's digits.

But the example says "1" and "11", which are digits.

But what if the number is written as a word? The problem does not specify. We'll assume digits for now.

However, the problem says: "1 hours and 11 minutes" -> so we have two numbers.

We can do:

tokens = "1 hours and 11 minutes to go".split()

We'll get: token[0] = '1' -> digit -> then check token[1] = 'hours' -> so add 1*60 then we see token[3] = '11' -> digit -> then token[4] = 'minutes' -> add 11

But note: the token after the number might not be the next one? Actually, in this example, it is.

However, what if we have: "1 hour 11 minutes" -> then the tokens would be: ['1','hour','11','minutes'] -> same.

But what about: "1 hour and 11 minutes" -> we have an extra 'and'. So we skip the non-digit tokens.

Our method: we are iterating and when we find a digit, we check the next token. Then we can skip the next token (because we used it) or we can just continue and the next token (which is a word) will be skipped because it's not a digit.

However, what if we have a number that is not followed by a unit? Then we skip? But the problem says the string is about time.

We'll assume that every number that is immediately followed by a unit (hour/hours/minute/minutes) is a time component.

But note: what if we have "1 hour and 30 minutes and 15 seconds"? We are only concerned with hours and minutes.

We are to convert to minutes, so we ignore seconds.

So we can do:

    tokens = s.split()
    total_minutes = 0
    i = 0
    while i < len(tokens):
        if tokens[i].isdigit():
            num = int(tokens[i])
            # Check next token if exists
            if i+1 < len(tokens):
                next_token = tokens[i+1].lower()
                if next_token in ['hour', 'hours']:
                    total_minutes += num * 60
                    i += 1   # skip the next token because we used it
                elif next_token in ['minute', 'minutes']:
                    total_minutes += num
                    i += 1   # skip the next token
        i += 1

However, note that the above loop increments i by 1 at the end of the loop always, and if we found a unit we skip the next token by doing an extra i+=1.

Example: i=0: token[0]='1' -> digit -> then token[1]='hours' -> so we add 60 and then set i=0+1 (from the skip) then at the end i becomes 1+1=2. Then i=2: token[2]='and' -> not digit -> then i becomes 3. i=3: token[3]='11' -> digit -> then token[4]='minutes' -> add 11, then set i=3+1=4, then at the end i becomes 4+1=5 -> then we break.

But wait, we skipped the unit token by doing i+=1 inside the if, and then the outer i+=1 moves to the next token after the unit.

However, we don't want to skip the unit token and then also skip the next token? Actually, we are at token i (the digit) and then we look at token i+1 (the unit). Then we skip the unit by doing i+=1 (so that we don't process the unit as a digit) and then the outer i+=1 moves to the token after the unit.

But what if we have consecutive numbers without units? We don't process them.

This should be acceptable.

However, what if the string is: "1 hours 30 minutes" -> then we have: tokens: ['1','hours','30','minutes'] i=0: digit -> next token 'hours' -> add 60, then set i=1 (inside the if) then outer i becomes 2. i=2: token[2]='30' -> digit -> then next token is 'minutes' -> add 30, then set i=3 (inside the if) then outer i becomes 4 -> done.

This works.

But what if the string is: "1 hour and 30" -> then we have: tokens: ['1','hour','and','30'] i=0: digit -> next token 'hour' -> add 60, then set i=1 -> then outer i becomes 2. i=2: token[2]='and' -> not digit -> i becomes 3. i=3: token[3]='30' -> digit -> then next token? i+1=4 -> out of range -> so we don't add.

But the string says "30" without a unit? Then we ignore. That's acceptable because we don't know the unit.

However, the problem says the string is "1 hours and 11 minutes to go", so we have both units.

But what if the string is: "1 hour 30" -> then we have: tokens: ['1','hour','30'] i=0: digit -> next token 'hour' -> add 60, then set i=1 -> then outer i becomes 2. i=2: token[2]='30' -> digit -> then next token? none -> skip.

So we miss the 30? But without a unit, we don't know if it's minutes or seconds? So we ignore.

We are only to consider tokens that are followed by the unit.

But note: what if the unit comes before the number? That's not typical. We assume the pattern: number then unit.

So we'll code accordingly.

However, the problem says: "1 hours and 11 minutes to go"

Let's test with that string:

    tokens = ['1','hours','and','11','minutes','to','go']

    i=0: token[0]='1' -> digit -> next token='hours' -> add 60, then set i=1 (so we skip the 'hours') -> then outer i becomes 1+1=2.
    i=2: token[2]='and' -> not digit -> i becomes 3.
    i=3: token[3]='11' -> digit -> next token='minutes' -> add 11, then set i=4 (skip 'minutes') -> then outer i becomes 4+1=5 -> then i=5: token[5]='to' -> skip -> i=6: done.

So total_minutes = 60+11 = 71.

We return 71.

But note: what if the string has a number that is not an integer? For example, "1.5 hours". We are using .isdigit(), which only returns true for integers. So we might need to handle floats.

However, the problem does not specify. We'll assume integers.

But let's consider: if we see a token that is a float? We can try to convert to float? But note: the token might have a decimal point.

We can do:

    if tokens[i].replace('.', '', 1).isdigit() and tokens[i].count('.')